Math, asked by shinchan1910, 5 months ago

(4ab-7bc+8ca) from ( 3ab+4bc-6ca)​

Answers

Answered by pulakmath007
1

SOLUTION

TO EVALUATE

To subtract

(4ab-7bc+8ca) from ( 3ab+4bc-6ca)

EVALUATION

We have to subtract

(4ab-7bc+8ca) from ( 3ab+4bc-6ca)

Hence the required result

= ( 3ab + 4bc - 6ca ) - ( 4ab - 7bc + 8ca )

= ( 3ab + 4bc - 6ca - 4ab + 7bc - 8ca )

= 3ab - 4ab + 4bc + 7bc - 6ca - 8ca

= - ab + 11bc - 14ca

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