Question

4Al + 3O2 → 2Al2O3 In this chemical reaction, how many grams of Al2O3 will be produced if 375 grams of Al react completely? Express your answer to three significant figures.

Answer 1

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Answer:

≈ 708

Explanation :

Here we have equation as:

4 Al + 3 O₂ → 2 Al₂O₃

As we know:

No of moles = Mass/ Molar mass

Here, Mass is 375 g and Molar mass is 27 gms, so no. of moles of Al will be:

=375 g /27 g/mol

= 13.889 mol

About mole ratio, we can see that for 4 moles of Al , 2 moles of Al2O3 are formed, so for 13.889 moles of Al, 13.889 mol ÷ 2 =6.944 moles of Al₂O₃ will be formed.

As we know:

Mass= No of moles/Molar mass

Mass= No of moles/Molar mass Mass of Al₂O₃ = 6.944 mol × 102 g/mol

= 708.288 g

= 708.288 g 708 of Al2O3 will be produced.

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Answer 2

Answer..

Here we have equation as:

4 Al + 3 O₂ → 2 Al₂O₃

As we know:

No of moles = Mass/ Molar mass

Here, Mass is 375 g and Molar mass is 27 gms, so no. of moles of Al will be:

=375 g /27 g/mol

= 13.889 mol

About mole ratio, we can see that for 4 moles of Al , 2 moles of Al2O3 are formed, so for 13.889 moles of Al, 13.889 mol ÷ 2 =6.944 moles of Al₂O₃ will be formed.

As we know:

Mass= No of moles/Molar mass

Mass= No of moles/Molar mass Mass of Al₂O₃ = 6.944 mol × 102 g/mol

= 708.288 g

= 708.288 g 708 of Al2O3 will be produced.