Question

4chairs and 3 tables cost rs2100 and 5chairs and 2 table cost rupees 1750 find the cost of one chair and one table separately

Answer 1

let the cost of 1 chair=₹x
let the cost of 1 table=₹y
now ATQ,
4x+3y=₹2100........................(1) ×2
5x+2y=₹1750.......................(2). ×3
from equation (1) and (2)
8x+6y=4200
- 15x+6y=5250
_____-___-_____
-7x=-1050
x=-1050/-7
x=150
from eq(1)
4x+3y=2100
putting the value of X in eq(1)
4×150+3y=2100
600+3y=2100
3y=2100-600
Y=1500/3
Y=500
Hence ,the cost of 1 chair=₹x=₹150. ANS
the cost of 1 table=₹y=₹500. ANS☺️☺️

Answer 2

Given data : 4 chairs and 3 tables cost Rs 2100 and 5 chairs and 2 tables cost Rs 1750.

Solution : Let, the cost of one chair be x and the cost of one table be y.

Now, according to the given data;

• 4x + 3y = 2100 ----{1}

• 5x + 2y = 1750 ----{2}

Now, multiply eq. {1} by 2

• 8x + 6y = 4200 ----{3} and similarly,

Multiply eq. {2} by 3

• 15x + 6y = 5250 ----{4}

Now, subtract eq. {3} from eq. {4}

15x + 6y = 5250

- (8 + 6y) = 4200

______________

7x = 1050

x = 1050/7

x = 150

Now, put value of x in eq. {1}

➜ 4x + 3y = 2100

➜ 4*(150) + 3y = 2100

➜ 600 + 3y = 2100

➜ 3y = 2100 - 600

➜ 3y = 1500

➜ y = 1500/3

➜ y = 500

Answer : Hence, the cost of one chair is Rs 150 and the cost of one table is Rs 500.

[Verification : Put vale of x and y in eq. {1}

➜ 4x + 3y = 2100

➜ 4*(150) + 3*(500) = 2100

➜ 600 + 1500 = 2100

➜ 2100 = 2100

Hence, it's verified]