4cos square A-1=0. find a if 0<a<90
Answers
Answered by
1
4cos^2A-1=0
4cos^2A=1
cos^2A=1/4
cosA =1/2
cosA= cos60°
A=60°
4cos^2A=1
cos^2A=1/4
cosA =1/2
cosA= cos60°
A=60°
Lazytriangle:
I can't
Similar questions