Question

A transformer converts 200v a.c to 50v a.c the secondary has 50 turns and load across it draws 300 mA current calculate
1) Number of turns in the primary
2) The power consumed.

Answer 1

Answer:

1) N = 200 turns

2) P = 15 Watt

Step by step explanation:

1) The number of turns is directly proportional to the potential difference in the coil for a transformer.

Therefore, $\frac{N_s}{N_p}=\frac{V_s}{V_p}$.

Where $N_s$ is the number of turns in the secondary coil, $N_p$ is the number of turns in the primary coil, $V_s$ is the potential difference in the secondary coil and $V_p$ is the potential difference in the primary coil.

Hence, $N_p=\frac{N_s*V_p}{V_s}\\ N_p=\frac{50*200}{50}=200$ turns.

2) P = I*V

P = 300mA * 50V = 15 W