Question

4coso=11sino, find 11coso-7sino/11coso+7sino​

Answer 1

Answer:

Now

4cos A =11 sinS

=>cos A /sin A = 11/4

=>11 cos A/ 7 sin A =( 11 x 11)/(4 x 7)

=>11cos A/7 sin A= 121/28

=>(11cos A + 7 sin A)/(11 cos A - 7sin A)

=(121+28)/(121-28)

[componendo&dividendo]

= 149/93

therefore

11 cos A - 7 sin A/11 cos A + 7 sin A

=93/149

Answer 2

Answer:

93/149

Step-by-step explanation:

if 4 cos A=11 sin A

tan A=4/11

11cosA-7sin A/11cosA+7sinA

if we divide the equation by cos A we will get:-

11-7tanA/11+7tanA

=121-28/11÷121+28/11

=93/11÷149/11

=93/149