4g argon in a bulb at a trmperature t kelvin has a pressure P atm when the bulb was placed in a hot bath at a temperature 50 degree centigrade more than the first one 0.8 g of gas had to be removed to get the original pressure. T is equal to
Answers
Answered by
300
P1 = n1.R.T1/V1
P1 = n2.R.T1 + 50/V1
n1.T1 = n2.T1 + 50
T1. n1/n2 - 1= 50
n1/n2 = m1/m2
T1.m1/m2 - 1= 50
T1.4.0 g / 3. 2 g - 1= 50
T1.1.25 - 1.00= 50
T1 = 50/ 0.25= 200 K
T = T1 = 200 K
Answered by
23
Answer:
200k
Explanation:
according to question..0.8 g gas has to be removed..so final volume left will be equal to initial volume(4)-O.8=3.2gm
and as pressure;volume ;R will be same or constant ....so n1t1=n2t2
plz refer to the attachment above
hope it helps
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