Question

4g H2 , 32g O2, 14g N2 and 11g CO2 are taken in a bulb of 500 ml. Which one of these has maximum active mass?

Answer 1

OK

here is the forumla for the active mass

Answer 2

4 g of H₂ = (4/2) moles of H₂ = 2 moles H₂

32 g of O₂ = (32/32) moles of O₂ = 1 moles of O₂

14 g of N₂ = (14/28) moles of N₂ = 0.5 moles of N₂

11 g of CO₂ = (11/44) moles of CO₂ = 0.25 moles of CO₂

Active mass of H₂ = 4 moles/litre

Active mass of O₂ = 2 moles/litre                  

Active mass of N₂ = 1 mole/litre

Active mass of CO₂ = 0.5 mole/litre

Thus H₂ has the maximum active mass.