Question

4g of He and n gm of CO2 at 25°c have same kinetic energie.what is the value of n 1. 44
2. 2
3. 22
4. 88

Answer 1

Answer:-n=44

Explanation:

w1/M1=n1/M2

4/4=n1/44 n=44

Answer 2

Given: 4g of He and n gm of CO2 at 25°c have the same kinetic energy.

To find: We have to find the value of n.

Solution:

The kinetic energy of gas can be given as 3/2nRT.

Where R is constant and T is the temperature of the gas.

n is the number of moles.

Here only n differs so, we can write-

$n_1=n_2$

Where $n_1,n_2$ are several moles of He and carbon dioxide.

$\dfrac{w_1}{M_1}=\dfrac{w_2}{M_2}$

Where w1 is the weight of He=4g.

w2 is the weight of carbon dioxide=ng.

M1 is the molecular weight of He =4g.

M2 is the molecular weight of carbon dioxide=44g.

Putting the values in the above formula we get-

$\frac{4}{4} = \frac{n}{44} \\ n = 44$

The value of n is 44.

The correct option is 1.