4log2+log3-2log2 express as log N
Answers
Answered by
19
4log2+log3-2log2=logN
logN=log2^4+log3-log2^2
logN=log(48)-log4
logN=log12
logN=log2^4+log3-log2^2
logN=log(48)-log4
logN=log12
pnasreen20:
I understood thanks
Answered by
8
4log2+log3-2log2
=log(2)^4*+log3/4**
=log16+log3/4
=log16×(3/4)*#
=log4×3
=log12
formula used:
*#logab=log a+log b
**log(a/b)=log a-log b
*log a^m=m log a
=log(2)^4*+log3/4**
=log16+log3/4
=log16×(3/4)*#
=log4×3
=log12
formula used:
*#logab=log a+log b
**log(a/b)=log a-log b
*log a^m=m log a
thank u for solution
i understand
you're welcome
Thank u i got it
Similar questions