Question

4log3×logx÷log 9= log27

Answer 1

$4log3×logx÷log 9= log27 \\ \\log3^{4} ×logx÷log 9= log27 \\ \\ log( {3}^{4} + x - 9 ) = log(27) \\ \\ {3}^{4} + x - 9 = 27 \\ \\ 81 - 9 + x = 27 \\ \\ 72 + x = 27 \\ \\ x = - 45$

Answer 2

Answer:

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