Question

4m-2n=-4 ; 4m+3n=16. Solve this equations by Cramer’s method.

Answer 1

Solution:-

given by:-
$4m - 2n = - 4...........(1) \\ 4m + 3n = 16............(2)$
Solving eq(1) and eq(2) by cramer's method
$Δ = \binom{4 \: \: \: \: - 2}{4 \: \: \: \: \: \: 3} = 12 + 8 = 20 \\ \\ Δx = \binom{ - 4 \: \: \: \: - 2 }{16 \: \: \: \: \: \: \: 3} = - 32 + 12 = - 20 \\ Δy = \binom{4 \: \: \: - 4}{4 \: \: \: \: \: \: 16} = 64 + 16 = 80 \\ x = \frac{Δx}{Δ} = \frac{ - 20}{20} = - 1 \\ y = \frac{Δy}{Δ} = \frac{80}{20} = 4$
here ( x , y ) = (-1 ,4)

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Answer 2

Answer:

HOPE THIS HELPS

BYE.

Step-by-step explanation:

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