Question

4m+6n=54 ; 3m+2n=28 Solve this equations by Cramer’s method.

Answer 1

SOLUTION IS IN THE ATTACHMENT..

Determinant method (Cramer’s Rule) :
In Cramer’s method, the equations are written as a1x + b1y = c1 & a2x + b2y = c2.

The value of determinant :
D = |a1 b1|
       |a2 b2|

D = a1b2 - a2b1

Dx = |c1 b1|
         |c2 b2|

Dx = c1b2 - c2b1

Dy = |a1 c1|
         |a2 c2|

Dy = a1c2 - a2c1

We find the value of x & y by using this formula:
x = Dx / D & y = Dy / D

HOPE THIS WILL HELP YOU…

Answer 2

Solution:-

given by:-
$4m + 6n = 54.........(1) \\ 3m + 2n = 28.........(2) \\ solving \: eq \:(1) \: ans \: eq(2) \: with \: cramer \: s \: method \: \\ Δ = \binom{4 \: \: \: 6}{3 \: \: \: 2} = 8 - 18 = - 10 \\ Δx = \binom{54 \: \: \: 6}{28 \: \: \: \: 2} = 108 - 168 = - 60 \\ Δy = \binom{4 \: \: \: 54}{3 \: \: \: \: 28 } \: = 112 - 162 = - 50 \\ x = \frac{ Δ x}{Δ} = \frac{ - 60}{ - 10 } = 6 \\ y = \frac{ Δ y}{Δ} = \frac{ - 50}{ - 10} = 5$
here (x , y ) = ( 6 , 5)