Question

6x-4y=-12 ; 8x-3y=-2 Solve this equations by Cramer’s method.

Answer 1

Final Answer:  x= 2 , y = 6 

Solution :  Cramer,s Rule :Most awesome Method to solve linear Equations 
Steps:
1) 
 We have,
                    6x-4y=-12 
                    8x-3y = -2 

2) Coeffcient Matrix : $\left[\begin{array}{cc}6&-4\\8&-3\end{array}\right]$
Determinant ,D = (6*-3)-(-4*8)=-18+32=14  

X-Matrix : $\left[\begin{array}{cc}-12&-4\\-2&-3\end{array}\right]$
Determinant,Dx = (-12*-3)-(-2*-4) =36-8=28   

Y-Matrix : $\left[\begin{array}{cc}6&-12\\8&-2\end{array}\right]$
Determinant ,Dy = (6*-2)-(8*-12) = -12+96=84 

3) Now, 
    By  Cramer's Rule,

   x= $\frac{D_x}{D} = \frac{28}{14} = 2$
   
   y= $\frac{D_y}{D} = \frac{84}{14} = 6$


Hence , $\boxed {x=2,y=6}$

Answer 2

SOLUTION IS IN THE ATTACHMENT..

Determinant method (Cramer’s Rule) :
In Cramer’s method, the equations are written as a1x + b1y = c1 & a2x + b2y = c2.

The value of determinant :
D = |a1 b1|
       |a2 b2|

D = a1b2 - a2b1

Dx = |c1 b1|
         |c2 b2|

Dx = c1b2 - c2b1

Dy = |a1 c1|
         |a2 c2|

Dy = a1c2 - a2c1

We find the value of x & y by using this formula:
x = Dx / D & y = Dy / D

HOPE THIS WILL HELP YOU…