4n^2+1204n-12440=0
solve this pls
Answers
Answered by
2
Answer:
4n²+1204n-12440=0
=> n²+301n-3110=0
=> n²+311n-10n-3110
=> n(n+311)-10(n+311)=0
=> (n+311)(n-10)=0
=> n= -311 or 10
Answered by
2
Answer:
(n+311)(n-10)=0
Step-by-step explanation:
n^2 + 301n-3110 = 0
n^2 +311n - 10n -3110 = 0
n(n+311)-10(n+311) = 0
(n+311)(n-10) = 0
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