Question

4n2-8n+3 factorise this question

Answer 1

Heya... ^-^

Here's ur ans. ------

4n^2 - 8n + 3

$4n {}^{2} - 6n - 2n + 3 = 0$

$2n(2n - 3) \: + 1(2n - 3)$

$(2n - 3) \: (2n \ + 1)$

$n = 3 \div 2 \: and \: - 1 \div 2$

✌ Hope it helps

Answer 2

Solution ●●●●
______________

$= 4 {n}^{2} - n(6 + 2) + 3$

$= 4 {n}^{2} - 6n - 2n + 3$

$= 2n(2n - 3) - 1(2n - 3)$

$= (2n - 3)(2n - 1)$
__________________________

I hope it will help you

⚽⚽⚽⚽⚽⚽⚽