Question

4p=4000, R = 12% N= 3 years . Find compound interest​

Answer 1

Answer:

(1) Here, P = ₹ 2000; R = 5 % ; N = 2 years

A=P(1+R100)N =2000(1+5100)2 =2000(105100)2 =2000(2120)2 =2205 Rupees∴ Compound Interest after 2 years,I = Amount − Principal =2205−2000 =205 Rupees

Hence, Amount = ₹ 2205 and Compound interest = ₹ 205.

Answer 2

Answer:

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