Math, asked by sakshikushwah702, 7 months ago

4p
In AABC a line drawn parallel
to BC cuts AB.AC at P and Q
respectively. Given AP:PB = 3:7
and area of AABC is 72 sq cm.
then the area of trapezium
PQCB is :-
52.65 sq cm
65.52 sq cm
55.62 sq cm
0 56.25 sq cm
Clear selection​

Answers

Answered by bishnu1717
0

Answer:

55.62 sq cm clear your answer .......

Answered by Anonymous
6

In ABC a line drawn parallel to BC cuts AB.AC at P and Q respectively. Given AP:PB = 3:7 and area of ABC is 72 sq cm. then the area of trapezium PQCB is :-

=> 55.62 sq.cm

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