Question

4power X = 5 power y = 20 power z then z is equal to

Answer 1

Answer:

let 4^x=5^y=20^z=k

taking log on both sides,

xlog4=ylog5=zlog20=log k

now, log 20 = log 4+log 5

and log4= logk/x and log 5= logk/y

So, zlog20= log k

z{log 4 +log 5}= log k

z[logk/x +logk/y]= log k

logk/x +logk/y = logk/z

1/x+1/y= 1/z

hope it will help you

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