Question

(4pq + 3q)² – (4pq – 3q)² = 48pq² show that​

Answer 1

Answer:

See the attachment.

Step-by-step explanation:

Answer 2

Answer:

LHS =  48pq²

RHS =  48pq²

48pq²  =  48pq²

LHS = RHS

Step-by-step explanation:

(4pq + 3q)² – (4pq – 3q)² = 48pq²

Identities of Algebraic expressions

(a + b)² = a² + b² + 2ab

(a – b)² = a² + b² – 2ab

So, we have to apply the above identities in the given equation.

LHS = (4pq + 3q)² – (4pq – 3q)²

= (16p²q² + 9q² + 24pq²) – (16p²q² + 9q² – 24pq²)

= 16p²q² + 9q² + 24pq² – 16p²q² – 9q² + 24pq²

= 24pq² + 24pq²

= 48pq²

LHS =  48pq²

RHS =  48pq²

48pq²  =  48pq²

LHS = RHS

Hence Proved