4root 12multipied by 7 root 16
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4root12 × 7root16
4×2root3 ×7×4
8root3×28
224root3 is answer obtained
4×2root3 ×7×4
8root3×28
224root3 is answer obtained
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first factorise 12=2x2x3 , then factorise 6=2x3
second, given 4√12 x 7√6 can be written as 4√2x2x3 * 7√2x3
and one more step , multiple like this 4x7√2x2x3x3x2
one 2 and one 3 comes out and one 2 is left inside root
4x7x2x3√2=168√2
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