4root3xsquare+5x-2root3=0
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4root3xsquare+8x-3x-2 root 3=0
4x (root3x+2)-root3 (root3x+2)=0
(4x-root3)(root3x+2)=0
x=root3/4 orx=-2/root3 ...or -2root3/3
....
.........!!!hope it help you
4x (root3x+2)-root3 (root3x+2)=0
(4x-root3)(root3x+2)=0
x=root3/4 orx=-2/root3 ...or -2root3/3
....
.........!!!hope it help you
Answered by
8
hi mate,
4√3 x² +5x -2√3 =0
⇒4√3 x² +8x -3x -2√3=0
⇒4x(√3 x+2) -√3(√3x +2) =0
⇒(√3x +2)(4x -√3) =0
⇒(√3x +2) =0 or (4x-√3) =0
⇒x = -2/√3 or √3/4
i hope it helps you.
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