Question

4s²-4s+1 quadratic polynomial​

Answer 1

4s² - 4s + 1 = 0

{Approach 1} :
(2s)² - 2.(2s).(1) + (1)² = 0
(2s - 1)² = 0
s = 1/2, 1/2

OR

{Approach 2} :
4s² - 2s - 2s + 1 = 0
2s(2s -1) - 1(2s - 1) = 0
(2s - 1) (2s - 1) = 0
s = 1/2, 1/2

Thankyou!!!

Answer 2

$\alpha + \beta = \frac{ - b}{a} \\ \\ \alpha \beta = \frac{c}{a } \\ where \: a = 4 \\ b = - 4 \: c = 1$

$( - b \frac{ + }{ - } \sqrt{ {b}^{2} } - 4ac) \div 2a$