Question

4sin2 60+3tan2 30_8sin45.cos45

Answer 1

This should be your answer.

Answer 2

Heya,

Given=>
4sin²60° + 3tan²30° - 8sin45°cos45°

sin60° = √3/2
tan30° = 1/√3
sin45° = 1/√2
cos45° = 1/√2

=> 4(√3/2)² + 3(1/√3)² - 8(1/√2)(1/√2)

=> 4×3/4 + 3×1/3 - 8/2

=> 3 + 1 - 4

=> 4 - 4

=> 0. ...... Answer

Hope this helps.....:)