Math, asked by luckthefire, 1 year ago

4tan^2theta= 3sec^2theta

Answers

Answered by rajuraj29
6
4 tan²¢ = 3sec²¢

4tan²¢ = 3 ( 1+ tan²¢ )

4tan²¢ - 3tan²¢ = 3

tan²¢ = 3

tan¢ = √3

tan¢ = tan60°

¢ = 60 °

Mr. perfect Rajuraj ;-)
Answered by jaya1012
6
Hiiii. .....friend

The answer is here,

Let the theta be x. for my convience.

 =  >  \: 4 {tan}^{2} x = 3 {sec}^{2} x

 =  >  \: 4 {tan}^{2} x - 3 {sec}^{2} x = 0

 =  >  \:  {tan}^{2}x +  3 {tan}^{2} x - 3 {sec}^{2} x =

 =  >  \:  {tan}^{2} x + 3( {tan}^{2}x -  {sec}^{2}x) = 0

 =  >  \:  {tan}^{2} x + 3( - 1) = 0

 =  >  \:  {tan}^{2} x = 3

 =  >  \: tanx =  \sqrt{3}

 =  >  \: x = 60

:-)Hope it helps u.
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