Question

4tan"B"=3 and if B is acute angle Cos "B"=×

Answer 1

Step-by-step explanation:

4tanB=3

TanB (opposite/adjacent) = 4/3

Hypotenuse side = sqrt(4^2+3^2)

=sqrt(25) = 5

then CosB = adjacent/Hypotenuse = 3/5

CosB=3/5

Hope it helps:)