Question

4tan theta =3 then {4sin theta -cos theta /4sin theta +cos theta }=?

Answer 1

Hey.. this is the answer.

Answer 2

Answer:

IF 4 tan = 3

then, (4 sin-cos)/(4 sin+cos)

Explanation:

4 tan = 3

tan = 3/4 = p/b

therefore, h = 5

$\frac{4 sin - cos}{4 sin+cos} \\=\frac{4\frac{3}{5}-\frac{4}{5} }{4 \frac{3}{5}+\frac{4}{5} } \\=\frac{\frac{12}{5}-\frac{4}{5} }{\frac{12}{5}+\frac{4}{5} }\\=\frac{\frac{8}{5} }{\frac{16}{5} }\\\\\ =\frac{8\\}{16}\\=\frac{1}{2}$