Question

4th one pls help me :( :)

Answer 1

Answer:

3 ,9,18 ,27,36

.

4,16,32,64,128

Answer 2

Given Question

Fill in the boxes

$\rm :\longmapsto\:\dfrac{3}{4} = \dfrac{\boxed{}}{16} = \dfrac{\boxed{}}{32} = \dfrac{27}{\boxed{}} = \dfrac{36}{\boxed{}}$

$\green{\large\underline{\sf{Solution-}}}$

Given data is

$\rm :\longmapsto\:\dfrac{3}{4} = \dfrac{\boxed{}}{16} = \dfrac{\boxed{}}{32} = \dfrac{27}{\boxed{}} = \dfrac{36}{\boxed{}}$

Let assume that

$\rm :\longmapsto\:\dfrac{3}{4} = \dfrac{\boxed{x}}{16} = \dfrac{\boxed{y}}{32} = \dfrac{27}{\boxed{z}} = \dfrac{36}{\boxed{w}}$

Taking first and second member, we have

$\rm :\longmapsto\:\dfrac{3}{4} = \dfrac{\boxed{x}}{16}$

On cross multiplication, we have

$\rm :\longmapsto\:4 \times x = 16 \times 3$

$\rm :\longmapsto\:4x = 48$

$\bf\implies \:x = 12$

Now, Taking first and third member, we have

$\rm :\longmapsto\:\dfrac{3}{4} = \dfrac{\boxed{y}}{32}$

$\rm :\longmapsto\:4 \times y = 32 \times 3$

$\rm :\longmapsto\:4y = 96$

$\bf\implies \:y = 24$

Now, Taking first and fourth member, we have

$\rm :\longmapsto\:\dfrac{3}{4} = \dfrac{27}{\boxed{z}}$

$\rm :\longmapsto\:3 \times z = 27 \times 4$

$\rm :\longmapsto\:3z = 108$

$\bf\implies \:z = 36$

Now, Taking first and fifth member, we have

$\rm :\longmapsto\:\dfrac{3}{4} = \dfrac{36}{\boxed{w}}$

$\rm :\longmapsto\:3 \times w = 36 \times 4$

$\rm :\longmapsto\:3w = 144$

$\bf\implies \:w = 48$

Hence,

$\rm :\longmapsto\:\dfrac{3}{4} = \dfrac{\boxed{12}}{16} = \dfrac{\boxed{24}}{32} = \dfrac{27}{\boxed{36}} = \dfrac{36}{\boxed{48}}$