Question

4th vertex of the rhombus whose 3 consecutive vertices are (-4,-0), (3,-1), (2,6) is​

Answer 1

Answer:

Diagonals of a parallelogram bisect each other,

let the point of intersection of diagonals be P(m,n)

m = (-4+2)/2 = -1

n = (0+6)/2 = 3

Let the fourth vertex of a parallelogram be (x,y)

m = (3+x)/2

-1 = (3+x)/2

x = 1

n = (-1+y)/2

3 = (0+y)/2

y = 6

Hence the fourth vertex is (1,6)

Answer 2

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