Math, asked by khushalpsai, 10 months ago

Factorise 3a^2b^3-27a^4b

Answers

Answered by pansumantarkm
62

Step-by-step explanation:

3a²b³ - 27a⁴b

=3a²b(b² - 9a²)

=3a²b[(b)² - (3a)²]

=3a²b[(b + 3a)(b - 3a)]. [(x² - y²) = (x + y)(x - y)]

=3a²b(b + 3a)(b - 3a)

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Answered by khushboodagar729
11

Answer:

3a^2b^3-27a^4b

3a^2b(b^2-9a^2)

3a^2b{(b)^2-(3a)^2}

3a^2b(b+3a) (b-3a)

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