Question

4u square + 8u find the zeroes​

Answer 1

Answer:

4u²+8u

= 4u(u+2)

=> 4u=0

=> u=0

and u+2=0

=> u= -2

therefore zeros are: 0 and -2

hope it helps u.... ^_^

Answer 2

Answer:

The equation is 4u2+8u

Taking 4u common

4u(u+2) = 0U+2

=0U

=-2.

ZEROS ARE 0 AND - 2.

Hope it helps.