Question

4x^2-19x+12=0
In completing square method​

Answer 1

Answer:

hlo❤☺gm

4x²-19x+12=0

4x²-(16+3) +12=0

4x²-16x-3x+12=0

4x(x-4) -3(x-4) =0

(4x-3) (x-4) =0

:.4x-3=0 or,( x-4) =0

4x=3 x=4

x=3/4

hope u like it ❣

Answer 2

${\huge{\mathfrak\red{hy \:mate}}}$

your answer is givin attachment ☺

${\huge{\mathbb\pink{Thanks,}}}$

❤ʕ •ᴥ•ʔ❤