Question

4x ^2 - 2(c + 1)x + (c + 4) = 0 has equal roots.
Find the value of c for which the quadratic equation

Answer 1

Step-by-step explanation:

You didn't mention the condition.

here, a=4 b=-2(c+1) c=c+4

If b²-4ac=0.

then,

(-2c-2)²-4(4)(c+4)=0

(-2(c+1)²-4(4)(c+4)=0

4(c²+1+2c)-16c-64=0

4c²+4+8c-16c-64=0

(4xf-8c-60=0)÷4

c²-2c-15=0

c²+5c-3c-15=0

c(c+5)-3(c+5)=0

(c-3)(c+5)=0

c=3 or -5.