Question

4x^2+3x+5=0 by quadratic formulae​

Answer 1

D = b^2 - 4ac

D = (3)^2 -4(4)(5)

D = 9 - 80

D = -71

It doesnt exist

Answer 2

4x^2 + 3x + 5 = 0

Here, a = 4 ; b = 3 ; c = 5

Quadratic formula : -b+-√b^2-4ac / 2a

-3+-√9-80 / 2(4)

-3+-√71 / 8

Therefore, values of ' x ' can be " -3+√71 /8 " (or) " -3-√71 / 8 ".