Math, asked by punamrajesh21, 4 months ago

4x^2-41x+72 solve answer should be 8​

Answers

Answered by nitusubedi2007
1

Answer:

4x^2-41x+72

4x^2-x(32+9)+72

4x^2-32x-9x+72x

4x(x-8)-9(x-8)

(4x-9) (x-8)

Answered by bhuwan567bj
1

Step-by-step explanation:

4x^2-41x+72=0

4x^2-32x-9x+72=0

4x(x-8)-9(x-8)=0

(4x-9)(x-8)=0

x not equal 9/4

x=8

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