factorise 8X cube + root 27 Y cube
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Step-by-step explanation:
We know the identity a
3
−b
3
=(a−b)(a
2
+b
2
+ab)
Using the above identity, the equation 8x
3
−27y
3
can be factorised as follows:
8x
3
−27y
3
=(2x)
3
−(3y)
3
=(2x−3y)[(2x)
2
+(3y)
2
+(2x×3y)]=(2x−3y)(4x
2
+9y
2
+6xy)
Hence, 8x
3
−27y
3
=(2x−3y)(4x
2
+9y
2
+6xy)
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