4x^2-49x(a^2-b^2) value of x
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To find x
4x²-49x(a²-b²)=0
x(4x-49(a²-b²))=0
x=0
and 4x-49(a²-b²)=0
4x=49(a²-b²)
x=49(a²-b²)/4
4x²-49x(a²-b²)=0
x(4x-49(a²-b²))=0
x=0
and 4x-49(a²-b²)=0
4x=49(a²-b²)
x=49(a²-b²)/4
jgxti:
Sorry but answer is a+b/2 , a-b/2
then your question is wrong
check the question once there is a mistake in it
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