Question

4x^2-4ax+(a^2-b^2)=0​

Answer 1

Step-by-step explanation:

2The given quadratic equation is 4x

2

−4ax+(a

2

−b

2

)=0

4x

2

−4ax+(a+b)(a−b)=0

⇒4x

2

+[−2a−2a+2b−2b]x+(a−b)(a+b)=0

⇒4x

2

+(2b−2a)x−(2a+2b)x+(a−b)(a+b)=0

⇒4x

2

+2(b−a)x−2(a+b)x+(a−b)(a+b)=0

⇒2x[2x−(a−b)]−(a+b)[2x−(a−b)]=0

⇒[2x−(a−b)][2x−(a+b)]=0

⇒2x−(a−b)=0,2x−(a+b)=0

⇒x=

2

a+b

,

2

a-b .2ab ,

hope it helps ❤️❤️

follow me ❤️

.

Answer 2

Answer:

4x²-4ax+(a²-b²)=0

4x²-4ax+(a-b)(a+b)=0

4x²+[-2a-2a+2b-2b]x+(a-b)(a+b)=0

4x²+(2b-2a)x-(2a+2b)x+(a-b)(a+b)=0

4x²+2(b-a)x-2(a+b)x+(a-b)(a+b)=0

2x[2x-(a-b)]-(a+b)[2x-(a-b)]=0

[2x-(a-b)][2x-(a+b)]=0

2x-(a-b)=0 or 2x-(a+b)=0

x=a+b/2 or a-b/2