4x^2 +4x + 1 find the zeroes
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4x² + 4x + 1 = 0
By Mid Term splitting,
4x² + 2x + 2x + 1 = 0
2x(2x + 1) + 1(2x + 1) = 0
(2x + 1) (2x + 1) = 0
as 2x+ 1 = 0
then x = -1/2
hence the zeroes of the polynomial are -1/2 and -1/2
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Answer:
Sol :- 4x^2+4x+1 =0
Now we factorise it
4x^2+2x+2x+1 =0
Now, we take 2x common from that
we get, 2x(2x+1) +1(2x+1) =0
we take (2x+1) common
(2x+1) +(2x+1) =0
Hence 2x+1 =0 , x =-1/2 is the only root of this equation
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