Question

A satellite is orbiting the earth at a distance of 42000 km in a circular orbit. It completes one revolution in 24hrs. Calculate its linear speed.
Options:- 10990 kmph, 10890 kmph, 11000 kmph, 11880 kmph

The answer is not 11000 kmph.

I need a step-by-step explaination please.​

Answer 1

Answer:

The linear speed of the satellite is 10995.57 km / hr.

Step-by-step explanation:

It is Given that ;

●Radius at which satellite is orbiting the earth,

r = 42,000 km

●Time taken to complete one revolution,

t = 24 hrs.

☆Therefore total distance covered is equal to 2*r

(* here is pi). So seed os given by

v = 2*r/t

v = 2* × 42,000km / 24h

■ v = 10995.57 km / hr ■

This is the required solution.

Hope it helps...

Learn more about speed here :

https://brainly.in/question/4284549