Question

(4x-2)(4x-2)+6x=25 solved my answer please

Answer 1

Answer :


$(4x - 2)(4x - 2) + 6x = 25 \\ \\ (4x - 2) {}^{2} + 6x = 25 \\ \\ use \: (a - b {)}^{2} = {a}^{2} + 2ab - {b}^{2} \: and \\ expand \: the \: expression \\ \\ ({4x})^{2} - 2 \times 4x \times 2 + {2}^{2} + 6x = 25\\ \\ 1 {6x}^{2} - 16x + 4 + 6x = 25 \\ \\ collect \: like \: terms \\ \\ 16 {x}^{2} - 16x + 6x + 4 = 25 \\ \\ 16 {x}^{2} - 10x + 4 = 25$

${16x}^{2} - 10x + 4 - 25 = 0 \\ \\ {16x}^{2} - 10x - 21 = 0 \\ \\ write \: - 10x \: as \: a \: difference \\ \\ {16x}^{2} + 14x - 24x - 21 = 0 \\ \\ factor \: out \: 2x \: and \: - 3 \: from \: the \: expressions \\ \\ 2x(8x + 7) - 3(8x + 7) = 0$

$factor \: out \: 8x + 7 \: from \: the \: expression \\ \\ (8x + 7)(2x - 3) = 0 \\ \\(2x - 3) = \frac{0}{(8x + 7)} \\ \\ 2x - 3 = 0 \\ \\ 2x = 3 \\ \\ x = \frac{3}{2} \\ \\ x = 1.5$


HOPE IT WOULD HELP YOU

Answer 2

16xsq.-8x-8x+4+6x=25
16xsq.-16x+6x+4=25
16xsq.-10x=25-4
16xsq.-x