4x^2 + 9y^2 = 40 and xy=2 find 2x + 3y
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Answered by
4
Given, (2x + 3y)
On squaring we get
(2x+3y)^2 = 4x^2 + 9y^2 + 12xy
= 40 + 12(2)
= 40 + 24
= 64.
(2x + 3y) = 8.
Hope this helps!
On squaring we get
(2x+3y)^2 = 4x^2 + 9y^2 + 12xy
= 40 + 12(2)
= 40 + 24
= 64.
(2x + 3y) = 8.
Hope this helps!
Answered by
5
4x² + 9y² = 40 .
xy = 2 .
Now, we know that ( a + b )² = a² + 2ab + b² .
So , ( 2x + 3y )² = ( 2x )² + ( 2.2x.3y ) + ( 3y )²
=> ( 2x + 3y )² = 4x² + 9y² + 12xy
Putting the values of 4x² + 9y² and xy , we get
( 2x + 3y )² = 40 + 12 * 2
=> ( 2x + 3y )² = 64 .
=> ( 2x + 3y ) = 8 . [ Answer ]
Hope it helps !!
xy = 2 .
Now, we know that ( a + b )² = a² + 2ab + b² .
So , ( 2x + 3y )² = ( 2x )² + ( 2.2x.3y ) + ( 3y )²
=> ( 2x + 3y )² = 4x² + 9y² + 12xy
Putting the values of 4x² + 9y² and xy , we get
( 2x + 3y )² = 40 + 12 * 2
=> ( 2x + 3y )² = 64 .
=> ( 2x + 3y ) = 8 . [ Answer ]
Hope it helps !!
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