Question

(4x^2/p-1)^2 expand the algebraic expression​

Answer 1

Answer:

$\frac{16x^{4}}{p^{2}}-\frac{8x^{2}}{p}+1$

Explanation:

we know the algebraic identity:

$\boxed {(a-b)^{2}=a^{2}-2ab+b^{2}}$

Expansion of the expression:

$(\frac{4x^{2}}{p}-1)^{2}$

=$\left(\frac{4x^{2}}{p}\right)^{2}-2\times\left(\frac{4x^{2}}{p}\right)\times1+1^{2}$

= $\frac{16x^{4}}{p^{2}}-\frac{8x^{2}}{p}+1$

Therefore,

$(\frac{4x^{2}}{p}-1)^{2} = \frac{16x^{4}}{p^{2}}-\frac{8x^{2}}{p}+1$

••••

Answer 2

Answer:

Step-by-step explanation: