4x +2y=10
3x +5y=11 Using substitution method
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// Solve equation [2] for the variable y
[2] 5y = -3x + 11 [2] y = -3x/5 + 11/5
// Plug this in for variable y in equation [1]
[1] 4x + 2•(-3x/5+11/5) = 10 [1] 14x/5 = 28/5 [1] 14x = 28
// Solve equation [1] for the variable x
[1] 14x = 28 [1] x = 2
// By now we know this much :
x = 2 y = -3x/5+11/5
// Use the x value to solve for y
y = -(3/5)(2)+11/5 = 1
Solution :
{x,y} = {2,1}
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