Question

4x+3ky = 15 and x-2y =16 the value of k is

Answer 1

Step-by-step explanation:

The given equations are:

(k+1)x+3ky+15=0, and

5x+ky+5=0

Since, the given equations are coincident, therefore

\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}

\frac{k+1}{5}=\frac{3k}{k}=\frac{15}{5}

Taking the first two terms, we have

k=14

Answer 2

Step-by-step explanation:

If the lines represented by the equation 4x + 3ky =15 and x - 2y =16 are parallel, then the value of k