Question

4x+3y=11 and 3x+4y=10 then find the value of x2-2xy+y2.​

Answer 1

Answer:

1

Step-by-step explanation:

4x+3y = 11...........(1)

3x+4y = 10..........(2)

multiply eq(1) by 3 and eq(2) by 4

12x+9y = 33

12x+16y =40

subtract from eq(3) and eq(4)

-7y = -7

y = 1

putting value of y in eq(1)

4x+3(1) = 11

4x = 8

x = 2

we know that

x^2+y^2-2xy = (x-y)^2

=== putting value of x and y in (x-y)^2

so, (2-1)^2

===> 1^2

===> 1

answer = 1

Answer 2

Given equations are
2x+3y=11−−−−(1)
2x−4y=−24−−−−(2)
Form (1)
2x+3y=11
⇒2x=11−3y
⇒x=
2
11−3y
​
−−−(3)
substituting x in(2)
2x−4y=−24
⇒2(
2
11−3y
​
)−4y=−24
⇒11−3y−4y=−24
⇒11−7y=−24
⇒7y=35
⇒y=35/7
⇒y=5.
putting y = 5 in (3)
x=
2
11−3(5)
​

⇒x=
2
11−15
​

⇒x=−4/2
∴x=−2.
Hence x = -2 and y = 5 is the solution of the
equation.
Now, we have to find m
y=mx+3 ∴m=−1
5=3(−2)+3
5−3=−2m⇒−2m=2
⇒m=−2/x=−1