Math, asked by tinadatir007, 1 month ago

4x+3y 17;3x+4y 18 graphical method​

Answers

Answered by chouhansantoshkumars
2

Answer:

The given equations are

The given equations are3x+4y=18 ...(i)

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1 2x

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1 2x −

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1 2x −+

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1 2x −+

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1 2x −+ 9y=

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1 2x −+ 9y= −

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1 2x −+ 9y= −5

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1 2x −+ 9y= −5

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1 2x −+ 9y= −5 1

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1 2x −+ 9y= −5 1

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1 2x −+ 9y= −5 1

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1 2x −+ 9y= −5 1 7y=21

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1 2x −+ 9y= −5 1 7y=21⇒y=3

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1 2x −+ 9y= −5 1 7y=21⇒y=3On putting y=3 in (i), we get

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1 2x −+ 9y= −5 1 7y=21⇒y=3On putting y=3 in (i), we get3x+12=18⇒3x=6⇒x=2

The given equations are3x+4y=18 ...(i)4x+3y=17 ...(ii)On multiplying (i) by 4 and (ii) by 3 and subtracting, we get12x+16y=72−1 2x −+ 9y= −5 1 7y=21⇒y=3On putting y=3 in (i), we get3x+12=18⇒3x=6⇒x=2∴x=2,y=3

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