Question

4x+3y-2z=0
x+3y-2z=0
x+y+z=27
solve for x, y, z ​

Answer 1

Answer:

x = 0, y = 10.8, z = 16.2

Step-by-step explanation:

explanation:

4x+3y-2z= 0 (eqn 1 )

x+3y-2z=0 (eqn 2)

x+y+z=27 (eqn 3)

by substracting eqn 2 from eqn 1, we get

x = 0

Now, multiplying eqn3 by 2, we get

2x+2y+2z=54. (eqn 4)

by adding eqn 4 and eqn 2, and put value of x as 0. we get

y = 10.8

put the value of x and y in any equation, we get

z = 16.2

hence, x = 0, y = 10.8 and z = 16.2

Answer 2

Step-by-step explanation:

i hope this helps

thanks for the question

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