Math, asked by harshrajpu, 10 months ago

4x-3y=8
6x-y=29/3
solve for x and y

Answers

Answered by arjun6068
2

Given

3x - y + 711 + 2 = 10     ---------------- ( 1 )

And

3x + 3y  = 65                  ----------------- ( 2 )

First we simplify equation 1 , As  :

By taking L.C.M. , we get

⇒33x - 11y  + 7 + 22 = 110 

⇒33x - 11y  = 81            ------- ( 3 )

From equation 2 , we get

⇒ y = 653 - x     ( Substitute that value of y  in equation 3 and get 

⇒33x - 11 ( 653 - x  ) = 81

⇒33x  - 7153 + 11x = 81 

⇒44x = 81 + 7153

⇒44x = 9583

⇒x  = 958132

x  = 7.25   Now We , substitute that value of x in equation 2 and get 

⇒3 ( 7.25 ) + 3y = 65 

⇒3y  = 65 - 21.75

⇒3y  = 43.25 

⇒y = 14.416  

So,

⇒xy  = 7.2514.416   = 0.50

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Answered by SirSumit
6

4x-3y=8 ----(1)

6x-y=29/3 -----(2)

Multiplying eq.(2) by 3 we get

18x-3y=28 -----(3)

Now subtracting (1) and (3) gives

4x-6x-3y-(-3y)=8-(29/3)

-2x=-5/3

hence x=5/6 ---(4)

using (4) in (1) we get

4(5/6)-3y=8

(10/3)-3y=8

-3y=8-(10/3)

-3y=-14/3

hence y=14/3


SirSumit: 18-3y=29 ----(3)
SirSumit: on adding 1) and 3) we get
arjun6068: yup
SirSumit: x=21/2
SirSumit: then on substituting the value of x in 1) we get
SirSumit: y=34/3
SirSumit: but check it once more
SirSumit: i may be mistaken
arjun6068: wait a sec i will inbox u
SirSumit: ya
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