Question

(4x+3y) power 3 class 9 polynomials
Using identity

Answer 1

Answer:

64x³+27y³+252xy

Step-by-step explanation:

(x+y)³=x³+y³+3xy(x+y)

= 64x³+27y³+3(4x*3y)(4+3)

= 64x³+27y³+3*12xy(7)

=64x³+27y³+36xy(7)

=64x³+27y³+252xy

Hope it helps...

Answer 2

Step-by-step explanation:

(4x+3y)^3 can be written as: (4x+3y)*(4x+3y)^2

now we will use the identity (a+b)^2=a^2 + b^2 + 2ab

now we will add the values to the identity :

(4x+3y)^2 = (4x)^2 + (3y)^2 + 2 * 4x * 3y = 16x^2 + 9y^2 +24xy

now we will multiply all the factors :

=(4x + 3y)*(16x^2 + 9y^2)

=(4x + 3y)*(16x + 9y)*(16x + 9y)